>>13375567no cap.
Each hand pushes with force F, causing a total force of 2F to be distributed among the bricks. By symmetry, there are two normal vectors on each brick (one to the left and one to the right). This means that the normal force on each brick is equal to F/N, where N is the number of bricks. Using Newton's Second Law vertically, we have 2f - mg = 0, where m is the mass of the brick and f is the friction force between the two bricks. We know that f = un, where n is the normal force and u is the coefficient of friction of brick on brick. Therefore, we arrive at our master formula that the force you must press on the bricks with is
F = N mg/2
So with an infinite amount of force, you can hold up infinitely many bricks.
