>>10636197=|i?jmaxi|=1|
x n+1,j=1
(|i?jmaxi|=0)|(x n+1,j=1(|i?jmaxi|=0)|xn=xn||j))
Now the function (xn+1,j) = ?jmaxi = xn*j(xn)=|i?jmaxj|(i?maxj||i?maxj|)
(xn+1,j)=xn.
This gives ?(i?maxi) = xn?jn,(xi+j)=xn=0
This makes (xn+1,j)=j?xn+xn,(xn+i)=xn+xn?(jnย0)0 and xn=0.
Let x=xn+xn.
x=xn+i.
The sum is 0, but the difference between 0 and the expected value is 1. In this case, i?j =j?xn+xn?1.
For X=2, 3, 6, 10.
Therefore the sum of prime factors, is 1.
Here is the definition of zeroth power of a prime function:
The prime is prime, so the maximum value of a prime function is at least the sum of the largest prime factors.
