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Anonymous Sun 18 Feb 08:13:19 2018 No.9525336 View Reply Original Report

Quoted By: >>9525339 >>9525342 >>9526046

i bet sci can't do it

Anonymous

Anonymous Sun 18 Feb 2018 08:15:55 No.9525339 Report

Quoted By:

>>9525336
don't you need numerical methods for this?

Anonymous

Anonymous Sun 18 Feb 2018 08:17:57 No.9525342 Report

Quoted By:

>>9525336
e^(?ln8 + i?^2[2n+1])
8^???^2[2n+1]

Basically a circle with all the rational angles missing.

Anonymous

Anonymous Sun 18 Feb 2018 08:22:48 No.9525351 Report

Quoted By:

-8 multiplied with itself pi times, durr

Anonymous

Anonymous Sun 18 Feb 2018 08:24:18 No.9525353 Report

Quoted By: >>9525358

Plug it into Wolfram

Anonymous

Anonymous Sun 18 Feb 2018 08:28:13 No.9525358 Report

Quoted By:

Anonymous

Anonymous Sun 18 Feb 2018 08:46:56 No.9525385 Report

Quoted By:

How do you multiply something by itself .14 times?

Anonymous

Anonymous Sun 18 Feb 2018 08:59:49 No.9525404 Report

Quoted By:

$\displaystyle<br />8^\pi cos \left ( \pi^2 \right ) + i \, 8^\pi sin \left ( \pi ^2 \right )<br />$

Anonymous

Anonymous Sun 18 Feb 2018 17:36:11 No.9526046 Report

Quoted By:

>>9525336

What's there to solve?

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