>>10311880sometimes you can group them.
Let's say you have y=6x^3+3x^2+16x+8
you can group them: (6x^3+3x^2)+(16x+8)
and factor out a common factor: 3x^2(2x+1)+8(2x+1)
and regroup: (3x^2+8)*(2x+1)
set both sides to zero and you know the rest
also if there is no constant then you can factor out the x and get a regular quadratic.
This works in such a vanishingly small number of cases that it doesn't really matter. I would recommend moving on as long as you can do the factoring.